Space Area Allocation in Banquet

SSpace Area Allocation in Banquet

Here is an example of a banquet seating plan for 350guests.31 guests on the top table.

SOME CONSTANTS

Size of the table: 6 Feet X 3 feet and 3Feet X 3 feet

Space Area Allocation in Banquet

The working aisle (space) between two sprigs is 6 feet (minimum).

The distance between the top table and sprig is: 3 feet (minimum)

Distance of sprigs and the top table from the walls of the banquet hall: 5 feet (minimum)

 The top table should be raised from the ground by a minimum of 6 inches to 1 foot so that each can see the guests who are seated on the top table.

Calculation:

Total number of guests = 350

Guests on top table =31

To know the length of the top table multiplies no. of guests on the top table by 27 inches.

So 31X 27 inches =837inches, divide by 12 to convert into feet.

So 837 / 12 =69.75 feet (rounded off to 72 feet(we can have 12 tables of 6’X3’).

So the length of Top table is =72 feet.

To know the number of sprigs, divide the length by9 feet (6 feet is the aisle+3 feet is the table width)

So number of sprigs = 72 divide by 9 = 8 sprigs

The number of guests to be seated on sprig: 350 – 31 = 319 guests.

To know how many guests will be sitting on each sprig=310 divide by 8 =40 guests that mean 20 guests on each side of the sprig

To know the length of the sprig multiply the number of guests on each side of the sprig by 27inches i.e.

20 x 27 =540 inches or 540 divide 12 =45 feet. (We can have 7 tables of 6’x3’ and one table of 3’X3’).

So the length of the sprig table will be =45 feet.

When one calculates how the sprig will fit within the length of the top table the calculation will be:

Number of sprigs=8Numbers

Working aisle(space)=6 feet

Width of table=3 feet.

So the number of work aisles are =7 because of the number of sprigs are=8.

The size of the room will be

LENGTH= 45 feet (size of sprig table)+3 feet(distance between top table and sprig table)+3feet( width of top table)+ 10 feet allowance (5 feet on top and bottom)= 61 feet, say = 65 feet.

WIDTH = 72 feet (Length of top table) + 10allowance feet (5 feet on top and bottom) = 82 feet, say= 85 feet.

The ideal size required for the above banquet is :

65 feet x 85 feet.

Amit Kumar
Amit Kumarhttp:////hmhelp.in
Hii! Welcome to My digital home, I am Amit – an almost no-code generalist, helping businesses with their online presence using WordPress and other tools and simplifying some of their operations with ideas and automation. A psychology and philosophy geek by interest and a graduate in Hospitality Management. I founded hmhelp during college, which got me into WordPress. I am a highly motivated and results-oriented professional with a proven track record of success in the hospitality industry. I’m also a Digital Marketing Enthusiast with significant academic and practical experience managing digital content across multiple platforms. Skilled at SEO optimization, developing digital content for social media platforms, I offer extensive knowledge of multiple software programs, strong attention to detail, and extraordinary communication skills. If you are interested in talking about any of the topics I have mentioned on my website, you are in the right place. You can contact me or learn more about what I do. You can also connect with me on social networks.

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